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Jan 14, 2018 at 2:32 history edited YCor
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Jan 13, 2018 at 22:40 history edited GH from MO
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Oct 19, 2014 at 18:59 vote accept Joseph O'Rourke
Oct 19, 2014 at 18:21 comment added Benoît Kloeckner Well, given any law on $\mathbb{N}$, you will see this kind of things happen: it is impossible to find a probability measure on $\mathbb{N}$ which gives weight $1/k$ to each of the classes modulo $k$, simultaneously for all $k$ (the weight of any number should be zero to meet that request).
Oct 19, 2014 at 11:47 history edited Joseph O'Rourke CC BY-SA 3.0
From n=2 rather than n=1.
Oct 19, 2014 at 11:36 comment added Joseph O'Rourke @JamieWeigandt: Indeed, I have added a similar image.
Oct 19, 2014 at 11:35 history edited Joseph O'Rourke CC BY-SA 3.0
added 210 characters in body
Oct 19, 2014 at 3:42 answer added Noam D. Elkies timeline score: 58
Oct 19, 2014 at 2:47 answer added Tony Huynh timeline score: 13
Oct 19, 2014 at 2:12 comment added James Weigandt This reminds me of the graph on page 31 here: amacad.org/publications/bulletin/spring2003/diaconis.pdf
Oct 19, 2014 at 2:00 history asked Joseph O'Rourke CC BY-SA 3.0