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Feb 12, 2015 at 13:54 vote accept Leandro Vendramin
Feb 11, 2015 at 14:51 comment added Geoff Robinson @Giuliano Bianco : F(G) is the Fitting subgroup of G. Since G has non-Abelian simple socle, the Fitting subgroup of G must be trivial, as must Z(G). I have fixed the reference to the simplicity of G- since G has no-Abelian simpe socle, G has trivial Fitting subgroup, so non non-identity element of G commutes with all its conjugates. – Geoff Robinson
Feb 11, 2015 at 11:28 history edited Geoff Robinson CC BY-SA 3.0
minor correction
Feb 11, 2015 at 11:21 comment added Giuliano Bianco @GeoffRobinson Also in the second answer, even after the last edit, you invoke (line 3) the simplicity of G, which is not in the hypothesis. By the way it is a really illuminating answer! Thank you prof. Robinson!
Feb 11, 2015 at 11:18 comment added Giuliano Bianco @GeoffRobinson By F(G) (in the first answer) you mean Z(G), or, for some reason, the Fitting subgroup or what?
Feb 11, 2015 at 10:09 history edited Geoff Robinson CC BY-SA 3.0
rewrote last proof more carrefully
Feb 10, 2015 at 19:28 history edited Geoff Robinson CC BY-SA 3.0
added different proof
Feb 2, 2015 at 17:34 comment added Geoff Robinson Possibly the first place it was recorded in the literature was in a paper of O.D. Artemovich in 1988 (see MR0952132)
Feb 2, 2015 at 17:25 comment added Leandro Vendramin Thanks! Would you have a reference for this generalization of the Glauberman Z*-theorem?
Oct 18, 2014 at 14:06 history edited Geoff Robinson CC BY-SA 3.0
typo and clarification
Oct 18, 2014 at 7:41 history answered Geoff Robinson CC BY-SA 3.0