Timeline for Are Banach space norms (up to equivalence) unique?
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
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| Aug 9 at 4:28 | comment | added | user152256 | to me is far from clear why the new norm given by $|x|:=\|Sx\|$ is complete, can you expand about this? | |
| Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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| Oct 15, 2014 at 12:31 | comment | added | Gerald Edgar | ... of course (as noted by Simon) that unbounded $\phi$ cannot be explicitly constructed. And cannot be constructed at all in simple ZF set theory. | |
| Oct 15, 2014 at 10:49 | vote | accept | Bernhard | ||
| Oct 15, 2014 at 10:48 | vote | accept | Bernhard | ||
| Oct 15, 2014 at 10:49 | |||||
| Oct 15, 2014 at 8:44 | history | answered | gsa | CC BY-SA 3.0 |