Timeline for A simple proof that parallelizable oriented closed manifolds are oriented boundaries?
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
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| Oct 15, 2014 at 14:37 | comment | added | Hugo Chapdelaine | Yes indeed, the anecdote behind your first answer is quite inspiring! | |
| Oct 15, 2014 at 11:44 | comment | added | András Szűcs | Sullivan invented it on the spot. | |
| S Oct 15, 2014 at 4:27 | history | suggested | CommunityBot | CC BY-SA 3.0 |
corrected "with fiber G" to "with total space G" and some minor spelling errors
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| Oct 15, 2014 at 3:53 | review | Suggested edits | |||
| S Oct 15, 2014 at 4:27 | |||||
| Oct 15, 2014 at 0:21 | comment | added | Hugo Chapdelaine | OK thanks! This is a very nice argument! | |
| Oct 14, 2014 at 21:08 | comment | added | András Szűcs | Sorry , I should have written cosets (instead of posets) | |
| Oct 14, 2014 at 21:07 | history | edited | András Szűcs | CC BY-SA 3.0 |
Sorry I wrote poset instead of coset. Is this clear now? I mean we consider the fibre bundle G \to G/S^1.
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| Oct 14, 2014 at 20:56 | comment | added | Hugo Chapdelaine | Dear Andras, what do you mean by "take all the posets"? | |
| Oct 14, 2014 at 20:25 | history | answered | András Szűcs | CC BY-SA 3.0 |