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Oct 20, 2014 at 15:50 vote accept Harry
Oct 15, 2014 at 10:17 vote accept Harry
Oct 17, 2014 at 11:44
Oct 14, 2014 at 17:42 comment added Steven Landsburg Multiplication by $1+i$ becomes a split injection mod $I$.
Oct 14, 2014 at 16:53 comment added Harry Thanks for your answer, but sorry I don't understand. I have the assumption that $R/I$ split injects into $S_I$ and the quotient maps respect all splittings. Hence the lift $R$ of can only embed as described above, and in particular not solely into $T$. So $\nu$ is not arbitrary...in fact I think I can show that $\nu$ is injective. So the question would reduce to whether or not it is split.
Oct 14, 2014 at 13:53 history answered Steven Landsburg CC BY-SA 3.0