Timeline for Lifting a direct summand of a free module
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 20, 2014 at 15:50 | vote | accept | Harry | ||
| Oct 20, 2014 at 15:50 | comment | added | Harry | Thanks again. I will accept your answer again since I can't accept this comment and I'm sorry that I can't up vote neither your answer nor your comment...looks that I don't have enough reputation, yet. | |
| Oct 20, 2014 at 13:30 | comment | added | Steven Landsburg | After your edit, the answwer is trivially yes: Split the map $R_I\rightarrow S_I$ with a map $f_I:S_I\rightarrow R_I$. Lift $f$ arbitrarily to a map $f:S\rightarrow R$. Then the composition $R\rightarrow S\rightarrow R$ is the identity mod $I$, hence an isomorphism. | |
| Oct 20, 2014 at 12:49 | history | edited | Harry | CC BY-SA 3.0 |
deleted 198 characters in body
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| Oct 17, 2014 at 11:44 | history | edited | Harry | CC BY-SA 3.0 |
added 376 characters in body
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| Oct 15, 2014 at 10:17 | vote | accept | Harry | ||
| Oct 17, 2014 at 11:44 | |||||
| Oct 14, 2014 at 13:53 | answer | added | Steven Landsburg | timeline score: 0 | |
| Oct 14, 2014 at 10:27 | review | First posts | |||
| Oct 14, 2014 at 10:28 | |||||
| Oct 14, 2014 at 10:26 | history | asked | Harry | CC BY-SA 3.0 |