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Dec 31, 2016 at 19:59 vote accept Eleven-Eleven
Sep 30, 2016 at 18:08 comment added Pietro Majer I understand that you want $\beta_k(x):=\sum_{n\ge0} b(n,k)x^n$: these are actually rational functions.
Sep 30, 2016 at 17:59 answer added Pietro Majer timeline score: 2
Oct 14, 2014 at 23:03 vote accept Eleven-Eleven
Dec 31, 2016 at 19:59
Oct 14, 2014 at 19:44 answer added Max Alekseyev timeline score: 5
Oct 14, 2014 at 19:26 comment added Eleven-Eleven I can see your point. Perhaps a non-rational then.....
Oct 14, 2014 at 5:18 comment added Amritanshu Prasad The recurrence relation in oeis.org/A008299: b(n+1,k) = kb(n,k) + nb(n-1,k-1) makes me wonder whether the ordinary generating function can be rational. Note the occurence of n in the second term.
Oct 14, 2014 at 2:55 comment added Eleven-Eleven Sorry...will do
Oct 14, 2014 at 2:45 comment added Todd Trimble Cross-posted from MSE: math.stackexchange.com/questions/971991/… Please do not cross-post without saying so. And please wait a while for an answer at one site before cross-posting to another.
Oct 14, 2014 at 2:04 history edited Eleven-Eleven CC BY-SA 3.0
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Oct 14, 2014 at 1:14 history edited Eleven-Eleven CC BY-SA 3.0
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Oct 14, 2014 at 1:01 review First posts
Oct 14, 2014 at 1:51
Oct 14, 2014 at 0:57 history asked Eleven-Eleven CC BY-SA 3.0