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Dec 21, 2013 at 14:30 history closed Ricardo Andrade
Andrey Rekalo
Olivier Benoist
Stefan Kohl
Daniel Moskovich
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Dec 21, 2013 at 1:57 review Close votes
Dec 21, 2013 at 14:30
Mar 18, 2010 at 14:47 comment added Regenbogen This question was best asked at the "Ask a topologist" forum.
Mar 16, 2010 at 17:17 answer added Anton Geraschenko timeline score: 4
Mar 16, 2010 at 16:59 comment added Kim Morrison There's always the disconnected cover by two copies of the base.
Mar 16, 2010 at 16:05 comment added Andrea Ferretti Is this homework?
Mar 16, 2010 at 15:05 comment added Andrew Stacey "covering map" implies local diffeomorphism which means that this is a strictly weaker question than that one as it assume strictly stronger conditions.
Mar 16, 2010 at 15:00 comment added Gerald Edgar What about a related question (which I think was also asked in MO once...) Does there exist a continuous f : R^n -> R^n that is exactly two-to-one ?
Mar 16, 2010 at 14:21 comment added Pete L. Clark No on $\mathbb{R}^n$ for all $n$ and $S^n$ for $n \geq 2$: these spaces are simply connected. Yes for $S^1$: $z \mapsto z^2$.
Mar 16, 2010 at 14:13 history asked Julgyz Harzum CC BY-SA 2.5