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Oct 9, 2014 at 18:37 comment added Martin Brandenburg Bonus question: Is there an example with finitely generated $k$-algebras?
Oct 9, 2014 at 18:32 comment added Martin Brandenburg I hope that the word "even" is not confusing: The rings also surject onto each other, hence also the underlying abelian groups, but that they are not isomorphic as rings does not necessarily imply that they are not isomorphic as abelian groups.
Oct 9, 2014 at 16:00 vote accept Dominic van der Zypen
Oct 9, 2014 at 14:13 history answered Martin Brandenburg CC BY-SA 3.0