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Oct 14, 2014 at 9:04 answer added Wolfgang Spindeler timeline score: 4
Oct 14, 2014 at 8:09 history edited dg.jan CC BY-SA 3.0
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S Oct 14, 2014 at 7:57 history suggested Wolfgang Spindeler
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Oct 14, 2014 at 7:32 review Suggested edits
S Oct 14, 2014 at 7:57
Oct 14, 2014 at 7:16 comment added Wolfgang Spindeler Here is a non-connected counterexample: Consider the example given in the second answer to this question: mathoverflow.net/questions/182719/…. Then let $X_i = X$ be the space defined there with $p_i = x$ and $p = y$. It is compact, but can easily be turned into a noncompact one by adding an infinite ray starting at $c$.
Oct 13, 2014 at 20:21 comment added YCor Anyway the same "joke" can hold in a connected space (e.g. use the union of the line $Im(z)=1$ and the segments $[n,n+i]$ for $n\in\mathbf{Z}$ in the complex plane, instead of $\mathbf{Z}$).
Oct 13, 2014 at 13:17 comment added dg.jan I added the hypothesis of connectedness of the metric spaces.
Oct 13, 2014 at 13:16 history edited dg.jan CC BY-SA 3.0
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Oct 9, 2014 at 13:43 comment added YCor Note that there are a few jokes: e.g. although $((1+1/n)\mathbf{Z},0)\to (\mathbf{Z},0)$, the closed 1-balls does not converge.
Oct 9, 2014 at 10:56 review First posts
Oct 9, 2014 at 10:56
Oct 9, 2014 at 10:49 history asked dg.jan CC BY-SA 3.0