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Oct 9, 2014 at 12:31 comment added Jean-Luc Bouchot Now I see what you mean. I do not have an example on the top of my head right now, no. Sorry!
Oct 8, 2014 at 13:29 comment added Paglia I am confused... In your counterexample there actually exists 1-sparse solutions, even if they are only 2. I am wondering if there are cases where $m$-sparse solutions of the problem do not exist.
Oct 8, 2014 at 12:30 history edited Jean-Luc Bouchot CC BY-SA 3.0
Added a counter example
Oct 8, 2014 at 12:28 comment added Jean-Luc Bouchot Consider the case where $N = 2$, $m = 1$ and take $A = [1,1] \in \mathbb{R}^{1 \times 2}$. Your optimization problem becomes, take $b \in \mathbb{R}^m$ as you wish, say $3$ $$\min \|(x,y)\|_1 \quad s.t. \;\; x+y = 3,$$ In this case, you have infinitely many solutions $\{(x,y): x = 3-y, 0 \leq y \leq 3 \}$. They all have a $\ell^1$ norm equal to $3$ and yet only $2$ of them are $1$-sparse.
Oct 8, 2014 at 8:07 comment added Paglia Thank you for the suggestions! By the way, do you now an explicit counterexample?
Oct 8, 2014 at 7:13 review First posts
Oct 8, 2014 at 8:06
Oct 8, 2014 at 7:10 history answered Jean-Luc Bouchot CC BY-SA 3.0