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Mar 22, 2021 at 8:29 history edited gmvh
Added top-level tag (post was bumped already)
Mar 22, 2021 at 8:16 answer added user111 timeline score: 2
Mar 22, 2021 at 7:35 comment added Fedor Petrov doi.org/10.3842/SIGMA.2018.056 looks related
Jun 2, 2019 at 17:27 comment added mamiladi i would like have the expression of $p_n$
Oct 5, 2014 at 20:38 comment added Twi Sorry, I certainly assume that the degree of $p_{n}$ is equal to $n$.
Oct 5, 2014 at 20:06 answer added Christian Remling timeline score: 2
Oct 5, 2014 at 19:37 comment added Joonas Ilmavirta @ChristianRemling, that is what I thought, but I could imagine that some other choice would come in an application. Vanishing at zero was a silly miscalculation; that would happen if the weight was not integrable near zero.
Oct 5, 2014 at 19:26 comment added Christian Remling @JoonasIlmavirta: There is a very standard procedure that gives unique $p_n$'s: you run Gram-Schmidt on $1,x,x^2,\ldots$ and make the leading coefficient positive. Also, there is no reason why the $p_n$ would have to vanish at zero.
Oct 5, 2014 at 16:44 comment added Joonas Ilmavirta The family of orthogonal polynomials with respect to a weight is not unique unless you make some restricting choices. Do you assume, for example, that $p_n$ has degree $n+1$? Note that all of your polynomials must vanish at zero.
Oct 5, 2014 at 16:29 history asked Twi CC BY-SA 3.0