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Oct 1, 2014 at 22:30 history edited Joe CC BY-SA 3.0
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Oct 1, 2014 at 20:49 answer added littlelittlelittle timeline score: 0
Oct 1, 2014 at 20:15 history edited Joe CC BY-SA 3.0
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Oct 1, 2014 at 20:06 answer added Michael Renardy timeline score: 1
Oct 1, 2014 at 20:00 comment added Rbega At the maximum value of $u$, $f$ must be negative, so you would also need an $f$ that changes sign -- i.e., the integral condition is not sufficient.
Oct 1, 2014 at 19:25 history edited Joe CC BY-SA 3.0
added 152 characters in body
Oct 1, 2014 at 19:15 history asked Joe CC BY-SA 3.0