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Jan 29, 2016 at 10:23 comment added Holonomia @Jao: I do not know if you are still interested but here is a possible answer. Take as $M$ a subgroup $H$ whose action is right-invariant (see mathoverflow.net/questions/229268/…). Then for $X,Y$ in the Lie algebra of $H$ you have $\overline{\nabla}_XY$ is always tangent to $M$ since $M$ is totally geodesic.
Sep 30, 2014 at 22:45 comment added user58848 That's right Ben McKay. Such that at every point $p \in M$ they are tangents to $M$
Sep 30, 2014 at 10:17 comment added Ben McKay ''such that in which $p \in M$ are'' means ''such that at every point $p \in M$ they are''?
Sep 29, 2014 at 20:09 review First posts
Sep 29, 2014 at 20:16
Sep 29, 2014 at 20:09 history asked Jao CC BY-SA 3.0