Timeline for Left invariant connection on Lie groups
Current License: CC BY-SA 3.0
5 events
when toggle format | what | by | license | comment | |
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Jan 29, 2016 at 10:23 | comment | added | Holonomia | @Jao: I do not know if you are still interested but here is a possible answer. Take as $M$ a subgroup $H$ whose action is right-invariant (see mathoverflow.net/questions/229268/…). Then for $X,Y$ in the Lie algebra of $H$ you have $\overline{\nabla}_XY$ is always tangent to $M$ since $M$ is totally geodesic. | |
Sep 30, 2014 at 22:45 | comment | added | user58848 | That's right Ben McKay. Such that at every point $p \in M$ they are tangents to $M$ | |
Sep 30, 2014 at 10:17 | comment | added | Ben McKay | ''such that in which $p \in M$ are'' means ''such that at every point $p \in M$ they are''? | |
Sep 29, 2014 at 20:09 | review | First posts | |||
Sep 29, 2014 at 20:16 | |||||
Sep 29, 2014 at 20:09 | history | asked | Jao | CC BY-SA 3.0 |