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Jul 27, 2017 at 20:21 answer added Roland Speicher timeline score: 4
Oct 31, 2016 at 14:42 comment added Federico Poloni Numerically, I've found that every eigenvector corresponding to a complex eigenvalue has a single real element. -- since you can multiply eigenvectors by an arbitrary scalar constant, this is probably just due to the normalization used in the numerical algorithm and has no real significance.
Oct 31, 2016 at 14:33 answer added Nicholas Simm timeline score: 7
Sep 18, 2014 at 12:41 vote accept Andrew
Sep 18, 2014 at 7:16 answer added Carlo Beenakker timeline score: 22
Sep 18, 2014 at 4:47 history edited Andrew CC BY-SA 3.0
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Sep 18, 2014 at 3:58 history edited Andrew CC BY-SA 3.0
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Sep 18, 2014 at 3:34 history edited Andrew
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Sep 18, 2014 at 3:27 review First posts
Sep 18, 2014 at 3:45
Sep 18, 2014 at 3:27 history asked Andrew CC BY-SA 3.0