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Timeline for Is Gauss sum a p-adic measure?

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Sep 13, 2014 at 18:52 history edited David Loeffler CC BY-SA 3.0
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Sep 13, 2014 at 16:30 comment added David Loeffler From the identity $G(\chi)G(\chi^{-1}) = N$ one can deduce that at least one of the factors has large valuation and that suffices for the above argument.
Sep 13, 2014 at 11:11 comment added KConrad Here is a reference. See R. Odoni, "On Gauss sums (mod $p^n$), $n \geq 2$," Bulletin London Math. Soc. 5 (1973), 325-327.
Sep 13, 2014 at 6:14 comment added user57657 Can you give a reference on determine the $p$-adic valuation of $G(\chi)$? The well-know fact is the complex norm of $G(\chi)$ is $\sqrt{N}$, if $N$ is the conductor of $G(\chi)$. Another result is Stickelberger's congruence. For me, it is not trivial to know the $p$-adic valuation of $G(\chi)$.
Sep 13, 2014 at 5:04 history answered David Loeffler CC BY-SA 3.0