Timeline for Proofs without words
Current License: CC BY-SA 3.0
9 events
when toggle format | what | by | license | comment | |
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Nov 12, 2017 at 7:30 | comment | added | მამუკა ჯიბლაძე | Well this might be actually interpreted as a visualization of the fact that squaring a sine/cosine curve produces another (shifted up) sine/cosine curve, viz. $\cos^2(x)=\frac12(1+\cos(2x))$ and $\sin^2(x)=\frac12(1-\cos(2x))$; in this way it comes closer to be a proof of something. | |
Aug 4, 2017 at 4:58 | history | edited | C.F.G | CC BY-SA 3.0 |
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Jul 18, 2016 at 13:29 | comment | added | Machinato | However, this could be a nice proof of $\int_{0}^{\pi/2}\sin^2 x\,\mathrm{d}x = \int_{0}^{\pi/2}\cos^2 x\,\mathrm{d}x = \frac{1}{2}\left(\frac{\pi}{2}\cdot 1\right)$ | |
Jun 25, 2015 at 18:53 | comment | added | Mario Carneiro | @StevenStadnicki In fact, I'm pretty sure that the function in the picture is not $\sin x$, the inflection point has a sharper third derivative than it should (although I'm sure this is just a limitation of the means by which the picture was drawn). There is certainly nothing geometrical constraining the shape of the diagram. | |
May 16, 2015 at 0:45 | comment | added | Steven Stadnicki | This is an exhibit of the fact, but it isn't really a proof - it doesn't explain why those two functions sum to 1, just shows (arguably, just claims) that they do. You could replace the curve with any function $f$ with $f(\pi/2)=1$. | |
Sep 11, 2014 at 10:42 | history | undeleted | Mostafa Mirabi | ||
Sep 11, 2014 at 7:59 | history | deleted | Mostafa Mirabi | via Vote | |
S Sep 11, 2014 at 7:24 | history | answered | Mostafa Mirabi | CC BY-SA 3.0 | |
S Sep 11, 2014 at 7:24 | history | made wiki | Post Made Community Wiki by Mostafa Mirabi |