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Sep 11, 2014 at 9:58 comment added Dmitry Kerner >>finiteness condition on R/m as an extension of $k$? $R$ is a local ring over the field $k$, so $R/\mathfrak{m}=k$. Or did you mean smth else?
Sep 11, 2014 at 9:57 comment added Dmitry Kerner Sorry, I'm confused and ignorant. Do you mean the restriction $R\rightarrow k$? In simple words, do you mean to impose that $GA$ is a scheme over $R$ and then to consider it over $k$? (And similarly to take the tangent space over $R$, then consider it over $k$?).
Sep 11, 2014 at 3:49 comment added S. Carnahan You can always use Weil restriction to get a tangent space object. Do you intend to impose any finiteness condition on $R/\mathfrak{m}$ as an extension of $k$?
Sep 10, 2014 at 22:37 history edited Ricardo Andrade CC BY-SA 3.0
removed tag 'proj'
Sep 10, 2014 at 8:47 history asked Dmitry Kerner CC BY-SA 3.0