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May 5, 2015 at 14:30 comment added Simon Henry @DominicvanderZypen : Here it is.
May 5, 2015 at 14:29 history edited Simon Henry CC BY-SA 3.0
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Apr 29, 2015 at 9:00 comment added Dominic van der Zypen Cool - I'm looking forward to the new formulatin!
Apr 29, 2015 at 8:37 comment added Simon Henry Well, I already do it before I asked the question, and I didn't find the answer myself. But you are right: even if I prefer the "geometric" formulation, it cannot arm to give a second a formulation with the detail of the construction. I will do it as soon as I have a bit more time.
Apr 29, 2015 at 8:18 comment added Dominic van der Zypen I believe the question would benefit from a re-formulation in terms of frames and the explicit construction of the pushout. Maybe doing this exact work, you even find the answer yourself!
Apr 19, 2015 at 11:56 comment added Simon Henry $S'$ is any frame. and the pushout depends on $S'$
Apr 17, 2015 at 14:15 comment added Dominic van der Zypen What is $S'$? Can you write down $P$ in terms of $S$ and $L$, and also the pushout map? Thanks!
Apr 17, 2015 at 11:35 comment added Simon Henry no you construct the pushout of $\iota$ along a map from $S$ to $S'$. And it will be the map from $L$ to the tensor product $L \otimes_{S} S'$ (the tensor product is the tensor product of sup-lattice). also note that not any frame monomorphism is a regular monomorphism.
Apr 17, 2015 at 9:27 comment added Dominic van der Zypen Sorry for bothering you with stupid questions. Let $L$ be a frame, $S\subseteq L$ be a subframe and $\iota:S\to L$ be the inclusion map. So $\iota$ is regular. Q1: How do we construct the pushout object $P$ along $\iota$, or in other words, what is $P$? Q2: The "pushout morphism", what does it look like, does it go from $P$ or into $P$? Many thanks.
Apr 14, 2015 at 9:21 comment added Simon Henry Yes. and locale monomorphism are just injective map, regular mono are equalizer of a pair of map (I don't know any nice characterisation), and by pushout I mean pushout (I.e. tensor product) along any frame morphism $X \rightarrow X'$.
Apr 14, 2015 at 9:04 comment added Dominic van der Zypen Excuse me for a basic question, but I prefer to think in the "original" directions of maps. So in terms of frames and the category $\textbf{Frm}$, your question would be: Given frames $X,Y$, and a regular frame monomorphism $\iota: X\to Y$, is the pushout of $\iota$ necessarily mono?
Sep 10, 2014 at 8:13 history asked Simon Henry CC BY-SA 3.0