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Sep 9, 2014 at 21:58 history edited Robert Israel CC BY-SA 3.0
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Sep 9, 2014 at 19:31 history edited Robert Israel CC BY-SA 3.0
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Sep 9, 2014 at 19:12 history edited Robert Israel CC BY-SA 3.0
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Sep 9, 2014 at 19:05 history edited Robert Israel CC BY-SA 3.0
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Sep 9, 2014 at 17:43 comment added Robert Israel Yes, that gives a slightly better upper bound, $\sqrt{\pi} c \sqrt{2 + 2 \exp(-c^2)}/4$. Still not sharp, I think.
Sep 9, 2014 at 10:16 comment added Geoff Robinson Can't the first estimate be combined with Cauchy Schwarz? Something like $\int_{0}^{\infty} \exp(-(x/c)^{2})|\cos(x)| dx \leq \sqrt{\int_{0}^{\infty} \exp(-(x/c)^{2})\cos^{2}(x)dx \int_{0}^{\infty} \exp(-(x/c)^{2})}dx$?
Sep 9, 2014 at 8:48 vote accept anonymous
Sep 8, 2014 at 18:49 history edited Robert Israel CC BY-SA 3.0
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Sep 8, 2014 at 18:41 history answered Robert Israel CC BY-SA 3.0