Timeline for Why is the supersingular locus the zero locus of a modular form?
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| Sep 6, 2014 at 18:36 | comment | added | Daniel Litt | @FelipeVoloch: Yes, I'm making the Hasse invariant essentially; my only complaint is that your construction would for example let one single out the curve of $j$-invariant $5$, whereas the Hasse invariant is somewhat more canonical. Your answer is of course perfect for the question as stated. | |
| Sep 6, 2014 at 18:23 | comment | added | Felipe Voloch | The Hasse invariant is a modular form of weight $p-1$ vanishing on the supersingular locus. This is basically what you are doing. The issue is the formulation of the question, really. | |
| Sep 6, 2014 at 18:15 | comment | added | Daniel Litt | (I've ignored all twists by cusps here, which are necessary to make this correct, I think.) | |
| Sep 6, 2014 at 18:13 | history | answered | Daniel Litt | CC BY-SA 3.0 |