Timeline for The necessary and sufficient condition for $\textbf{global}$ conformal flatness of a n-dim (pseudo-)Riemannian manifold
Current License: CC BY-SA 3.0
13 events
| when toggle format | what | by | license | comment | |
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| Sep 11, 2014 at 6:48 | vote | accept | 346699 | ||
| Sep 7, 2014 at 7:05 | answer | added | Vladimir S Matveev | timeline score: 5 | |
| Sep 6, 2014 at 7:24 | history | edited | 346699 | CC BY-SA 3.0 |
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| Sep 5, 2014 at 15:42 | answer | added | Robert Bryant | timeline score: 7 | |
| Sep 5, 2014 at 12:37 | comment | added | 346699 | @RobertBryant No. Maybe my original question is too general, and I'm not sure which assumption will be required. So you can add some assumptions you need to get some results. | |
| Sep 5, 2014 at 12:30 | comment | added | Robert Bryant | Also, are you assuming compactness or completeness or anything else global for the initial pseudo-Riemannian structure? | |
| Sep 5, 2014 at 12:27 | comment | added | 346699 | @RobertBryant Sorry, I have modified. | |
| Sep 5, 2014 at 12:25 | comment | added | Robert Bryant | I see. Most people call these 'pseudo-Riemannian manifolds'. Do you assume that the 'metric' is nowhere degenerate? | |
| Sep 5, 2014 at 12:24 | history | edited | 346699 | CC BY-SA 3.0 |
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| Sep 5, 2014 at 12:22 | comment | added | 346699 | @RobertBryant the metric is not necessarily positive definite, such as Lorentzian manifold. | |
| Sep 5, 2014 at 12:18 | comment | added | Robert Bryant | What you mean by a 'generalized Riemannian manifold'? Do you just mean a 'general Riemannian manifold'? | |
| Sep 5, 2014 at 11:58 | history | edited | 346699 | CC BY-SA 3.0 |
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| Sep 5, 2014 at 11:51 | history | asked | 346699 | CC BY-SA 3.0 |