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Sep 6, 2014 at 17:53 comment added Vít Tuček It is a bit unclear what exactly are you asking for. For $\mathrm{GL}(n, \mathbb{C})$ the theory of Schur functors give projectors to all irreducible submodules of $\otimes^k \mathbb{C}^n$. For the orthogonal or symplectic group it works in the same way on the space of harmonic tensors which are the subspace of of the full tensor power on which all traces are zero. So you can first project to harmonic tensors and then use a Schur functor.
Sep 5, 2014 at 13:28 comment added Grobi Grobsen Thanks, but I did not see an explicit formula for the projectors or a way to extract them from this. Am I missing something?
Sep 4, 2014 at 16:23 comment added Vít Tuček See Symmetry, Representations, and Invariants by Goodman and Wallach. The decomposition of tensor you are looking for are in Appendix F, which is freely available on Goodman's website: math.rutgers.edu/~goodman/repbook.html
Sep 4, 2014 at 15:57 review First posts
Sep 4, 2014 at 15:57
Sep 4, 2014 at 15:53 history asked Grobi Grobsen CC BY-SA 3.0