Timeline for Are Besov spaces $B^{s}_{p,q}$ invariant under Fourier transform?
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 5, 2014 at 7:32 | comment | added | Bazin | The equality $\sum_{k\ge 0}\phi_k(\xi)=1$ is equivalent to $\sum_{k\ge 0}\phi_k(D)=Id.$ | |
| Sep 4, 2014 at 14:48 | comment | added | Inquisitive | thanks; would you please tell me, why $\|u\|_{L^{1}}= \|\sum_{k\geq 0}\phi_{k}(D)u\|_{L^{1}}$?(I guess, I need to use $\sum_{k=0}^{\infty}\phi_{k}(\xi)=1$ but I don,t know how); thanks | |
| Sep 4, 2014 at 13:13 | history | answered | Bazin | CC BY-SA 3.0 |