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Sep 9, 2014 at 18:19 comment added Jim Bryan @BoyuZhang: everything is orientation preserving (my automorphism is even algebraic and hence preserves the complex structure and orientation). You have to interpret the description the automorphism of the graph correctly: the swapping of the two vertices is done by rotation, not reflection.
Sep 8, 2014 at 19:15 comment added Boyu Zhang I have just read Daniele Zuddas's answer. It seems that his construction is very similar to yours but he added another reflection to make it orientation-preserving. Thank you so much for your help! I have accepted his answer, but I will vote yours up as well.
Sep 8, 2014 at 19:11 comment added Boyu Zhang Thank you so much for your help. But it seems that your example is not orientation-preserving. If we look at the third model for the example, when we swamp the two vertices, the orientation seems to be reversed. Am I correct?
Sep 4, 2014 at 16:37 comment added Daniele Zuddas I see! actually, the construction of my answer is the topological counterpart of this.
Sep 4, 2014 at 15:22 history edited Jim Bryan CC BY-SA 3.0
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Sep 4, 2014 at 15:20 comment added Jim Bryan @abx yes you are correct about needing a third root of unity in this example. I'm going to edit the answer thanks.
Sep 4, 2014 at 15:19 comment added Jim Bryan @DanieleZuddas: the projectivization is singular so one has to normalize to get the "smooth projective model".
Sep 4, 2014 at 9:26 comment added Francesco Polizzi In fact, the answer to the question is yes. I give another construction in my answer below. If I read correctly Broughton's table, $n=6$ is actually the only possibility, so basically there is only one example.
Sep 4, 2014 at 8:57 comment added Francesco Polizzi @abx: ok, you are right.
Sep 4, 2014 at 8:54 comment added abx @Francesco Polizzi: the Euler number excludes a free action of a finite group, but your automorphism may have no fixed points while some power has fixed points.
Sep 4, 2014 at 8:52 comment added abx The curve is smooth but, as Francesco observes, the automorphism has 2 fixed points at infinity. One should take e.g. $(x,y)\mapsto (\omega x,-y)$ for the same curve, with $\omega $ a nontrivial third root of unity.
Sep 4, 2014 at 8:38 comment added Francesco Polizzi Are you sure of this example? The Euler number of a genus $2$ surface is $-2$, it seems to me that this forbids free cyclic actions on it. Am I missing something?
Sep 4, 2014 at 4:57 comment added Daniele Zuddas The projectivization of this curve seems to be singular at $[0,1, 0]$.
Sep 4, 2014 at 4:15 history answered Jim Bryan CC BY-SA 3.0