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Nov 9, 2017 at 13:45 history edited Dominic van der Zypen CC BY-SA 3.0
edited title
Sep 2, 2014 at 13:04 vote accept Dominic van der Zypen
Sep 2, 2014 at 12:53 comment added Dominic van der Zypen That's correct - I put the absolute value signs in the wrong place and edited the post now accordingly.
Sep 2, 2014 at 12:45 history edited Dominic van der Zypen CC BY-SA 3.0
I had the |..| bars for absolute value wrong
Aug 29, 2014 at 8:59 vote accept Dominic van der Zypen
Sep 2, 2014 at 12:49
Aug 28, 2014 at 22:29 answer added Noam D. Elkies timeline score: 3
Aug 28, 2014 at 15:57 comment added Fedor Petrov Something very strange is written. Looks like a misprint.
Aug 28, 2014 at 12:34 history edited Gerald Edgar
edited tags
Aug 28, 2014 at 12:34 comment added Gerald Edgar This is not what one means by "approximation theory". So I added "diophantine-approximation" ... maybe that's what this is?
Aug 28, 2014 at 9:08 comment added Włodzimierz Holsztyński As it's now, for $\ u=v=1\ $ the difference is always the smallest (for any real, not just for positive rational numbers). You're possibly thinking about the absolute value of each side of the inequality. But the sums of elements of $U$ form a discrete set. Thus the answer is still NO (again for arbitrary reals).
S Aug 28, 2014 at 8:59 history suggested Daniel Valenzuela CC BY-SA 3.0
grammar corrections
Aug 28, 2014 at 8:55 review Suggested edits
S Aug 28, 2014 at 8:59
Aug 28, 2014 at 8:47 history asked Dominic van der Zypen CC BY-SA 3.0