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Timeline for Are linear algebraic groups rigid?

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Aug 28, 2014 at 10:29 history edited Qfwfq CC BY-SA 3.0
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Aug 28, 2014 at 3:54 answer added user54268 timeline score: 10
Aug 28, 2014 at 3:43 comment added user54268 @StephenGriffeth: Yes, though I'd prefer to say "infinitesimally rigid" (and be explicit about the connectivity assumption; hmm, perhaps fibral connectivity can be dropped, but I haven't thought it through). The proof rests on quite a bit of the theory of reductive group schemes in SGA3.
Aug 28, 2014 at 2:04 comment added Stephen @user54268 So, you are saying that reductive groups are rigid, yes?
Aug 28, 2014 at 2:00 comment added user54268 If $G$ and $H$ are smooth affine group schemes with connected reductive fibers over an artin local ring $R$ (with arbitrary residue field) and their geometric special fibers are isomorphic then the functor ${\rm{Isom}}(G,H)$ is represented by a disjoint union of smooth affine $R$-schemes, as can be checked over a finite etale cover that splits $G$ and $H$ (and then using etale descent, which is avoids some effectivity problems since Spec($R$) is a fat point). Thus, an isomorphism of special fibers (if one exists) always lifts to an $R$-isomorphism.
Aug 28, 2014 at 1:57 comment added Stephen @Tony Pantev Huh. I guess I just wrote down this. For some reason your comment didn't show up while I was writing my answer...
Aug 28, 2014 at 1:56 answer added Stephen timeline score: 5
Aug 28, 2014 at 1:48 comment added Tony Pantev The group law on a unipotent algebraic group deforms non-trivially in general. For instance by scaling the symplectic form you get a one parameter deformation of the three dimennsional Heisenberg group (upper triangular $3\times 3$ matrices with ones on the diagonal) to the additive group of a $3$ dimensional vector space.
Aug 27, 2014 at 23:35 history asked Qfwfq CC BY-SA 3.0