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Aug 26, 2014 at 14:12 vote accept Lucien
Aug 25, 2014 at 11:34 answer added Vít Tuček timeline score: 2
Aug 25, 2014 at 10:52 comment added Venkataramana My confusion is what are "real points"? There is no ${\mathbb R}$-structure on $G/P$, a priori, unless $G$ and $P$ are defined over $\mathbb R$.
Aug 25, 2014 at 10:41 comment added YCor Could you clarify: what do mean by "is"? $(G/P)(\mathbf{R})$ is a set, a topological space, a real analytic manifold... A compact riemannian symmetric space is a metric space, a Riemannian manifold, a topological space, a real analytic manifold...
Aug 25, 2014 at 10:10 history asked Lucien CC BY-SA 3.0