Timeline for Finding integer points on elliptic curves via divisibility conditions like $(a+b)^2 \mid (2b^3+6ab^2-1)$
Current License: CC BY-SA 3.0
13 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 24, 2014 at 19:24 | answer | added | GH from MO | timeline score: 20 | |
| Aug 24, 2014 at 17:48 | answer | added | Lucia | timeline score: 20 | |
| Aug 24, 2014 at 6:22 | answer | added | Aaron Meyerowitz | timeline score: 3 | |
| Aug 24, 2014 at 2:51 | comment | added | Todd Trimble | Kieren, I hope you don't mind the edit. I just wanted to make sure the post was in the form of a question. | |
| Aug 24, 2014 at 2:50 | history | edited | Todd Trimble | CC BY-SA 3.0 |
put the post in the form of a question
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| Aug 24, 2014 at 2:17 | history | edited | Kieren MacMillan | CC BY-SA 3.0 |
Tried to incorporate the suggestions given in the related Meta thread.
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| Aug 23, 2014 at 21:36 | comment | added | Todd Trimble | See also the meta thread: meta.mathoverflow.net/questions/1865/… | |
| Aug 23, 2014 at 18:39 | comment | added | Kieren MacMillan | As I said in the MSE thread, the exact equation I'm trying to solve can be written as $(5b-a+1)(a+b)^2=2(2b^3+6ab^2-1)$, and I happen to know, based on how I derived this form, that the only solution is $(a,b)=(4,1)$. But I'm interested in figuring out a general method to attack this class of divisibility problems. | |
| Aug 23, 2014 at 18:36 | comment | added | Kieren MacMillan | Maxima brute-force calculations, mostly. A different form of it might be true: If $\alpha > \beta$ satisfies the hypothesis, then the quotient is $1$ or $\alpha > 2(\beta+1)$. I'd also be happy to have a counterexample found. | |
| Aug 23, 2014 at 18:32 | comment | added | GH from MO | Why do you think the conjecture is true? | |
| Aug 23, 2014 at 18:24 | review | Close votes | |||
| Aug 24, 2014 at 5:55 | |||||
| Aug 23, 2014 at 18:03 | history | edited | Kieren MacMillan | CC BY-SA 3.0 |
Corrected the proposition statement.
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| Aug 23, 2014 at 17:47 | history | asked | Kieren MacMillan | CC BY-SA 3.0 |