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Timeline for Continuous relations?

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Aug 25, 2014 at 20:12 comment added Lehs @Eric Wofsey: is the composition of continuous relations continuous according to your definition?
S Aug 25, 2014 at 19:56 history suggested Lehs CC BY-SA 3.0
made the definition easier to find and refer to
Aug 25, 2014 at 19:54 review Suggested edits
S Aug 25, 2014 at 19:56
Aug 24, 2014 at 10:33 comment added Eric Wofsey @JoonasIlmavirta: That definition will give you closed relations, which are not very well-behaved other than being symmetric in $X$ and $Y$. They are not closed under composition and include functions that are not continuous as functions. If you replace $K$ by $Y$ (so you are looking locally only on $X$), you get my definition of continuity (since it is local on the domain).
Aug 24, 2014 at 10:06 comment added Joonas Ilmavirta @NikWeaver, if $X$ and $Y$ are locally compact Hausdorff, wouldn't it be a natural attempt to define that a relation $R\subset X\times Y$ is continuous if $R\cap(C\times K)$ is continuous for all compact $C\subset X$ and $K\subset Y$?
Aug 23, 2014 at 22:17 comment added Nik Weaver A natural next question is the locally compact Hausdorff case ...
Aug 23, 2014 at 20:48 comment added Dimitri Chikhladze "Homomorphic relations" or modules can be also defined between relational algebras, and that might coincide with your general definition of the continuous relation.
Aug 23, 2014 at 20:46 comment added Dimitri Chikhladze General topological spaces can also fit into the algebraic picture. Topological spaces are relational algebras for the ultrafilter monad. For a relational algebra the structure map $TA \rightarrow A$ is a relation, i.e. morphisms of $Rel$. The algebra equations are replaced by inclusions of relations, i.e. 2-cells of $Rel$. This reflects the fact that in the non-compact Hausdorff case ultrafilters can converge to any number of points.
Aug 23, 2014 at 18:28 history edited Eric Wofsey CC BY-SA 3.0
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Aug 23, 2014 at 18:16 history edited Eric Wofsey CC BY-SA 3.0
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Aug 23, 2014 at 17:32 history edited Eric Wofsey CC BY-SA 3.0
previous edit was incorrect
Aug 23, 2014 at 17:20 history edited Eric Wofsey CC BY-SA 3.0
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Aug 23, 2014 at 16:54 history edited Eric Wofsey CC BY-SA 3.0
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Aug 23, 2014 at 16:46 comment added Lehs Limit needs Hausdorff, but has it to be an operator? If you use a relation instead, wouldn't then a general topology be generated from the relation: $x_\alpha C x \Leftrightarrow$ "$x$ is a condensation point of $x_\alpha$"?
Aug 23, 2014 at 16:44 history edited Eric Wofsey CC BY-SA 3.0
added 47 characters in body
Aug 23, 2014 at 15:40 history answered Eric Wofsey CC BY-SA 3.0