Timeline for Controling mixed derivatives
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 15, 2018 at 5:51 | comment | added | AlexR | @Hans It‘s been a while. I will look in my notes when I find the time. | |
| Jan 13, 2018 at 19:28 | comment | added | Hans | @AlexR: Why don't you post your complete answer below now that you have it? | |
| Sep 11, 2014 at 11:39 | comment | added | AlexR | I have finally come around the estimate using your suggestion with a little more care put into the $z$ dependency. Since your answer gave me the necessary hint (to look at specific terms and try to estimate them uniformly), I accept it :) | |
| Sep 11, 2014 at 11:37 | vote | accept | AlexR | ||
| Aug 23, 2014 at 12:53 | comment | added | AlexR | Actually the authors need the power of $z$ in the estimate to be $N$, at least for the $N=2$ case. They later use that $$\int_0^\infty e^{-ix_n t} \chi(t) t^{z+k-1} \mathrm dt \le C_2 \frac{(1+|z+k-1|)^2}{\Re z + k} (1+|x_n|)^{-\Re z -k} \le C (1+|z|)^2 (1+|x_n|)^{-\Re z-k}$$ | |
| Aug 22, 2014 at 8:34 | history | edited | Willie Wong | CC BY-SA 3.0 |
added 27 characters in body
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| Aug 22, 2014 at 8:28 | history | answered | Willie Wong | CC BY-SA 3.0 |