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Jun 22, 2022 at 7:16 history edited CommunityBot
replaced http://front.math.ucdavis.edu/ with https://arxiv.org/abs/
Aug 21, 2014 at 15:21 comment added Mikhail Ostrovskii @YCor (Yves) Thank you for the comments.
Aug 21, 2014 at 15:21 comment added Mikhail Ostrovskii @Bill Free products of groups mentioned in the remark.
Aug 21, 2014 at 15:04 comment added Bill Johnson What other classes of f.g. groups do Lipschitz embed into $L_1$?
Aug 21, 2014 at 9:54 comment added YCor To answer your question, it would be a good PhD work to prove that any non-virtually-abelian nilpotent f.g. group (or, more naturally, any non-abelian simply connected nilpotent Lie group) has no bilipschitz embedding into $L^1$.
Aug 21, 2014 at 9:52 comment added YCor There is not one Gromov random group, there is a recipe providing plenty of groups (and moreover it sometimes means those finitely presented groups containing these infinitely presented groups when they are arranged to be recursively presentable).
Aug 21, 2014 at 3:21 history asked Mikhail Ostrovskii CC BY-SA 3.0