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Aug 22, 2014 at 1:43 comment added Joseph Van Name You don't need to use one of the special metrization theorems since we are dealing with locally compact spaces. In particular, a locally compact space is metrizable if and only if it can be written as a disjoint union of second countable spaces (this little result follows easily from the fact that metric spaces are paracompact and every paracompact locally compact space is a disjoint union of $\sigma$-compact spaces). Also, it does not seem too difficult to show that this space is a disjoint union of second countable spaces using the fact that $X$ space is locally compact and metrizable.
Aug 21, 2014 at 3:45 history edited user46747 CC BY-SA 3.0
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Aug 21, 2014 at 2:26 history asked user46747 CC BY-SA 3.0