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Aug 20, 2014 at 18:45 comment added Jeremy Rickard @ParksJonehan There is always a finitely generated (in fact, cyclic) module whose projective dimension is equal to the global dimension of the ring. So $W$ can be chosen to be finitely generated, in which case, if the global dimension is finite and the ring is noetherian, its minimal projective resolution is a bounded complex of finitely generated projectives, so $W$ is perfect.
Aug 20, 2014 at 2:54 comment added Parks Jonehan We know that objects in $A-perf$ are bounded complexes of finite generated projective A-modules, why $W \in A-perf$?
Aug 19, 2014 at 23:37 history edited David White CC BY-SA 3.0
Fixed tex typo
Aug 19, 2014 at 21:53 history answered Alex Dugas CC BY-SA 3.0