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Aug 18, 2014 at 20:45 answer added Goldstern timeline score: 4
Aug 18, 2014 at 19:54 answer added Joel David Hamkins timeline score: 6
Aug 18, 2014 at 2:06 comment added Ioachim Drugus @Goldstern, I am not sure how the constants in the language of a set theory correlate with whether there is an axiomatization with bounded quantifiers only, of the set theory or of a fragment of it - probably, I am missing something. Also, I am not interested in a set theory of hereditarily finite sets (I don't know how you figured out those links are about such sets - those which I access don't mention hereditarily finite sets). But ZF (with infinitary axiom), NBG, or even Generalized Set Theory of Boolos, are good for this question.
Aug 18, 2014 at 1:42 comment added Ioachim Drugus Really, there is no clash of two terms - thanks. But since many authors use the term "restricted quantifier" I would prefer it.
Aug 17, 2014 at 22:24 comment added Emil Jeřábek Occurrences of variables that are not free are bound rather than bounded, so this doesn’t clash with the standard term “bounded quantifier”.
Aug 17, 2014 at 21:54 comment added Goldstern The tag "set theory" indicates to me that you might be interested in a theory that includes a version of the axiom of infinity. But the references in the wikipedia article seem to deal with computations with hereditarily finite sets only.
Aug 17, 2014 at 21:48 comment added Goldstern What language are you thinking of? ZF is often written in a purely relational language (with no constant symbols), so there won't be any closed formulas in which all quantifiers are bounded. It seems to me you need at least the constant $\omega$. Which function symbols do you want to allow? Power set? Smallest your favorite cardinal above $\alpha$?
Aug 17, 2014 at 16:52 history asked Ioachim Drugus CC BY-SA 3.0