Timeline for Definition of 'Koszul Ring' (in BGS)
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
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| Aug 15, 2014 at 18:46 | comment | added | Alex Zorn | That seems to mean 'The free left R-module underlying R is a semisimple module'. Thanks! | |
| Aug 15, 2014 at 18:12 | comment | added | Pablo Zadunaisky | You are right, they see $A_0$ as the quotient $A/A_{> 0}$. As for the condition of $A_0$ being semisimple, they mean "$A_0$ is a semisimple ring". | |
| Aug 15, 2014 at 16:22 | history | asked | Alex Zorn | CC BY-SA 3.0 |