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Aug 15, 2014 at 11:07 comment added Mikhail Katz @Teri, Perhaps you should reformulate your question accordingly.
Aug 14, 2014 at 8:15 comment added Teri Thanks! that's indeed a nice example. I have a vague impression (but haven't worked out any details) that if the space has the additional property that every global geodesic can be uniquely extended to a (locally) geodesic line, then the local geodesics are also unique. If so, this would mean that one cannot have a (complete) Riemannian manifold as an example.
Aug 14, 2014 at 8:09 vote accept Teri
Aug 12, 2014 at 14:56 comment added Pablo Lessa Thanks! After looking at chapter 8 I believe you now :).
Aug 12, 2014 at 14:04 comment added Mikhail Katz books.google.co.il/…
Aug 12, 2014 at 13:42 comment added Pablo Lessa I don't believe you :). If $\beta_x$ is the minimizing geodesic joining each $x$ on $\alpha$ to $p$. What's the limit of $\beta_x$ when $x$ converges to $q$? Are you saying this goes to $\alpha$? Proof or reference?
Aug 12, 2014 at 13:20 comment added Mikhail Katz No, $q$ is the "last" point with a unique minimizer.
Aug 12, 2014 at 13:15 comment added Pablo Lessa Aren't $p$ and $q$ joined by two minimizing geodesics?
Aug 12, 2014 at 13:08 history answered Mikhail Katz CC BY-SA 3.0