Timeline for Do regular conditional distributions almost surely assign trivial measure to all members of the conditioning $\sigma$-algebra?
Current License: CC BY-SA 3.0
16 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
|
|
Aug 13, 2014 at 20:47 | vote | accept | Julian Newman | ||
Aug 13, 2014 at 20:46 | answer | added | Julian Newman | timeline score: 4 | |
Aug 12, 2014 at 2:57 | history | edited | Julian Newman | CC BY-SA 3.0 |
deleted 7 characters in body
|
Aug 12, 2014 at 2:39 | history | edited | Julian Newman | CC BY-SA 3.0 |
added 7 characters in body
|
Aug 12, 2014 at 2:07 | history | edited | Julian Newman | CC BY-SA 3.0 |
added 1765 characters in body
|
Aug 11, 2014 at 22:25 | answer | added | Yuri Bakhtin | timeline score: 1 | |
Aug 11, 2014 at 22:21 | answer | added | Algernon | timeline score: 2 | |
Aug 11, 2014 at 16:09 | comment | added | Julian Newman | I've "revamped" the question to take into account the papers you've informed me of. Thank you very much for your help. | |
Aug 11, 2014 at 16:08 | history | edited | Julian Newman | CC BY-SA 3.0 |
deleted 349 characters in body; edited title
|
Aug 11, 2014 at 14:56 | comment | added | Julian Newman | Thanks. I think this answers my second question, but not my first (unless I read the papers too quickly). | |
Aug 11, 2014 at 14:30 | history | edited | Julian Newman | CC BY-SA 3.0 |
added 364 characters in body
|
Aug 11, 2014 at 13:06 | comment | added | Jochen Wengenroth | I think that this projecteuclid.org/euclid.aop/1015345764 answers your question. | |
Aug 11, 2014 at 12:27 | comment | added | Jochen Wengenroth | I have deleted my answer (which in fact did not answer the question). Meanwhile, I think that the answer to you question is NO. It might be helpful to study (more carefully than I did) the following projecteuclid.org/… | |
Aug 11, 2014 at 12:15 | comment | added | Julian Newman | I realise (thanks to Jochen Wengenroth) that I should perhaps emphasise: In the case that $\mathcal{E}$ is countably generated, the answer to both questions is yes, since clearly, for each $E \in \mathcal{E}$, $\rho_x^\mathcal{E}(E)=\mathbf{1}_E(x)$ a.e. (and then the $\pi$-$\lambda$ theorem gives the result, by considering a countable $\pi$-system generating $\mathcal{E}$). The difficulty in my questions is specifically due to the fact that I haven't assumed $\mathcal{E}$ to be countably generated. (I've only assumed $\Sigma$ to be countably generated, since $\Sigma$ is standard.) | |
Aug 11, 2014 at 2:47 | history | asked | Julian Newman | CC BY-SA 3.0 |