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Timeline for Morphisms of supermanifolds

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Mar 11, 2010 at 5:20 comment added Chris Schommer-Pries For supermanifolds of a more exotic flavor the same essential argument works, but you need to work with maps of sheaves rather then algebras. You can still mod out by nilpotents and obtain a map of underlying ordinary manifolds. I'm pretty sure the question was about the generic smooth setting, where the above answer applies directly.
Mar 11, 2010 at 5:15 vote accept Vamsi
Mar 11, 2010 at 5:15
Mar 11, 2010 at 5:07 comment added Kevin H. Lin fpqc: Yes, you are correct.
Mar 11, 2010 at 4:51 comment added Harry Gindi Ordinary smooth manifolds, right? I am pretty sure that this is not true for analytic or complex manifolds because this approach of determining the manifold by its global algebra of smooth functions is only valid by using partitions of unity.
Mar 11, 2010 at 4:44 history answered Chris Schommer-Pries CC BY-SA 2.5