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Timeline for Morphisms of supermanifolds

Current License: CC BY-SA 2.5

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Mar 11, 2010 at 5:44 history edited S. Carnahan CC BY-SA 2.5
correction
Mar 11, 2010 at 5:43 comment added S. Carnahan Oh, yeah. Reduction is a quotient. Editing...
Mar 11, 2010 at 5:25 comment added Chris Schommer-Pries Careful! It is dangerous to think of $C^\infty(\mathbb{R})$ as sitting inside the functions on $\mathbb{R}^{1|2}$ because such an inclusion is not natural/functorial/canonical. If you act by an automorphism of $\mathbb{R}^{1|2}$, this inclusion of algebras changes. You are not really "restricting" to $C^\infty(\mathbb{R}$. Rather it is better to quotient by nilpotents, which is a functorial construction. You then obtain the map on $C^\infty(\mathbb{R})$ as the induced map.
Mar 11, 2010 at 5:15 vote accept Vamsi
Mar 11, 2010 at 5:15 vote accept Vamsi
Mar 11, 2010 at 5:15
Mar 11, 2010 at 5:12 vote accept Vamsi
Mar 11, 2010 at 5:15
Mar 11, 2010 at 4:40 history answered S. Carnahan CC BY-SA 2.5