Timeline for An inequality involving traces and matrix inversions
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
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| Aug 16, 2014 at 22:24 | vote | accept | borntotry83 | ||
| Aug 16, 2014 at 18:29 | answer | added | M. Lin | timeline score: 1 | |
| Aug 8, 2014 at 13:09 | history | edited | borntotry83 | CC BY-SA 3.0 |
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| Aug 8, 2014 at 13:02 | history | edited | borntotry83 | CC BY-SA 3.0 |
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| Aug 8, 2014 at 12:21 | comment | added | john mangual | I don't know if it helps -- but this looks like out of a quantum information theory book. | |
| Aug 8, 2014 at 12:09 | comment | added | user56203 | I believe we can assume $B$ is positive definite, without a loss of generality. In fact, if we set $B(\varepsilon)=B+\varepsilon I$ with small $\varepsilon>0$, then both sides of the inequality become continous functions of $\varepsilon$ at point $\varepsilon=0$ (unless $\operatorname{trace}(B)=0$ which is equivalent to $B=0$). In other words, it is sufficient to prove the inequality with $B(\varepsilon)$ instead of $B$, that is, in the case when $B$ is invertible. | |
| Aug 8, 2014 at 11:55 | comment | added | Dietrich Burde | Crossposting: math.stackexchange.com/questions/890062/…. | |
| Aug 8, 2014 at 11:08 | review | First posts | |||
| Aug 8, 2014 at 11:11 | |||||
| Aug 8, 2014 at 11:05 | history | asked | borntotry83 | CC BY-SA 3.0 |