Timeline for Combination of two recent problems about finite groups of square orders
Current License: CC BY-SA 3.0
5 events
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| Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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| Apr 13, 2017 at 12:19 | history | edited | CommunityBot |
replaced http://math.stackexchange.com/ with https://math.stackexchange.com/
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| Aug 9, 2014 at 0:06 | comment | added | Aaron Meyerowitz | Since there is only one example for $m=24$ (according to the mentioned problems) maybe you should start by looking at it. You need to find subsets $A,B$ with $AA^{-1} \cap BB^{-1}=\{{1\}}$. It would help to have the two sets intersected be small. Hence one might try things like finding a subgroup of order $12$ (if there are such) and taking $A$ as a union of two (right) cosets. Then $AA^{-1}$ would have order at most $12+24\cdot 12=300.$ To do the same thing for $B$ you would need a different subgroup disjoint from the first (except $1$.) | |
| Aug 8, 2014 at 18:18 | history | edited | Arturo Magidin | CC BY-SA 3.0 |
fix formatting
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| Aug 8, 2014 at 6:13 | history | asked | M.H.Hooshmand | CC BY-SA 3.0 |