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Aug 7, 2014 at 22:32 history edited Joël CC BY-SA 3.0
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Aug 7, 2014 at 22:31 comment added Joël You're right. I correct.
Aug 7, 2014 at 17:30 comment added Jeremy Rickard $H^1(G,\mathbb{F}_p)=0$, so I think you mean $H^1(G,M)=0$ in your second paragraph?
Aug 7, 2014 at 17:22 history edited Joël CC BY-SA 3.0
added 5 characters in body
Aug 7, 2014 at 17:15 history answered Joël CC BY-SA 3.0