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Aug 23, 2016 at 15:00 vote accept Julien Bernard
S Aug 7, 2014 at 12:48 history suggested Jaap Eldering CC BY-SA 3.0
TeX-ify question
Aug 7, 2014 at 12:46 review Suggested edits
S Aug 7, 2014 at 12:48
Aug 6, 2014 at 15:44 answer added Jaap Eldering timeline score: 6
Aug 6, 2014 at 15:26 comment added Julien Bernard I think that the usual argument for smooth dependence on initial conditions does not work at zero just because the notion of a geodesic with the zero vector as initial tangent vector has no meaning. It is not a legitimate initial condition for the equation of geodesics.
Aug 6, 2014 at 15:10 comment added GH from MO Please use TeX on this site.
Aug 6, 2014 at 14:42 comment added Thomas Rot Why doesn't the normal argument for smooth dependence on initial conditions work at zero?
Aug 6, 2014 at 14:22 comment added Julien Bernard If I am right, concerning the differentiability properties of the exponential map, Gauss'lemma tells you only that the exponential map has first order derivatives at the origine(that is: the identity), but it tells you nothing about high order derivatives.
Aug 6, 2014 at 13:48 comment added Thomas Rot Yes it is, and there is more: en.wikipedia.org/wiki/Gauss's_lemma_(Riemannian_geometry)
Aug 6, 2014 at 13:17 review First posts
Aug 6, 2014 at 13:34
Aug 6, 2014 at 13:17 history asked Julien Bernard CC BY-SA 3.0