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Aug 7, 2014 at 1:05 vote accept Jason Siefken
Aug 6, 2014 at 16:57 answer added Dave L Renfro timeline score: 3
Aug 6, 2014 at 6:28 comment added Jason Siefken @Shamisen The property that I have used is if $(X,T)$ and $(Y,S)$ are dynamical systems with $f\circ T = S\circ f$ and $f$ is onto, then if $f$ has this property, $(X,T)$ minimal implies $(Y,T)$ is minimal. Though this follows quickly from the density property.
Aug 6, 2014 at 2:07 comment added Nate Eldredge Here's a note: A sufficient condition for $f : X \to Y$ to have this property is that there is an open set $U \subset X$ such that $f$ is continuous on $U$, and $f(U) = f(X)$. If so, then on $X \setminus U$, $f$ can be as discontinuous as it likes.
Aug 6, 2014 at 2:02 comment added Tadashi Just for the sake of curiosity, can you give more interesting properties of this generalization? Thanks :)
Aug 5, 2014 at 22:26 answer added Robert Israel timeline score: 1
Aug 5, 2014 at 22:11 comment added Robert Israel I wouldn't call this "semi-continuity", since upper and lower semi-continuity have nothing to do with this.
Aug 5, 2014 at 21:42 comment added Jason Siefken I do. The question has been corrected.
Aug 5, 2014 at 21:41 history edited Jason Siefken CC BY-SA 3.0
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Aug 5, 2014 at 21:35 comment added Anthony Quas The empty set is open. Do you mean $f^{-1}U$ contains a non-empty open set whenever $U$ is a non-empty open set?
Aug 5, 2014 at 20:54 history asked Jason Siefken CC BY-SA 3.0