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Andrés E. Caicedo
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Let $A$ be a definable subset of $\mathbb{R}$ in $\mathsf{ZF}$, and let $\mathcal{M},\mathcal{N}\models\mathsf{ZF}$ such that $A$ is lebesgue measurable in both models.

Is $\mu^\mathcal{M}(A^\mathcal{M})=\mu^\mathcal{N}(A^\mathcal{N})$?

Are there any conditions (applied to $A$ or $\mathcal{M},\mathcal{N}$) under which we know more about this question?

Let $A$ be a definable subset of $\mathbb{R}$ in $\mathsf{ZF}$, and let $\mathcal{M},\mathcal{N}\models\mathsf{ZF}$ such that $A$ is lebesgue measurable in both models.

Is $\mu^\mathcal{M}(A^\mathcal{M})=\mu^\mathcal{N}(A^\mathcal{N})$?

Let $A$ be a definable subset of $\mathbb{R}$ in $\mathsf{ZF}$, and let $\mathcal{M},\mathcal{N}\models\mathsf{ZF}$ such that $A$ is lebesgue measurable in both models.

Is $\mu^\mathcal{M}(A^\mathcal{M})=\mu^\mathcal{N}(A^\mathcal{N})$?

Are there any conditions (applied to $A$ or $\mathcal{M},\mathcal{N}$) under which we know more about this question?

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Measure of the same set in different models of ZF

Let $A$ be a definable subset of $\mathbb{R}$ in $\mathsf{ZF}$, and let $\mathcal{M},\mathcal{N}\models\mathsf{ZF}$ such that $A$ is lebesgue measurable in both models.

Is $\mu^\mathcal{M}(A^\mathcal{M})=\mu^\mathcal{N}(A^\mathcal{N})$?