Timeline for Why does this antisymmetric product factor out a determinant?
Current License: CC BY-SA 3.0
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| Mar 27, 2015 at 3:28 | history | edited | darij grinberg | CC BY-SA 3.0 |
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| Jul 29, 2014 at 23:13 | comment | added | Greg Egan | That's a wonderful generalisation! I had tried to use the Cauchy-Binet formula on the original problem, but I couldn't see how to make it fit. | |
| Jul 29, 2014 at 12:54 | history | edited | darij grinberg | CC BY-SA 3.0 |
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| Jul 29, 2014 at 12:45 | history | edited | darij grinberg | CC BY-SA 3.0 |
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| Jul 29, 2014 at 12:28 | history | edited | darij grinberg | CC BY-SA 3.0 |
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| Jul 29, 2014 at 12:09 | history | edited | darij grinberg | CC BY-SA 3.0 |
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| Jul 28, 2014 at 23:51 | comment | added | Greg Egan | This looks perfect to me. I'll have to think about non-generic $M$; so long as $M_q$ still has a right inverse maybe we can argue by continuity from the generic case. | |
| Jul 28, 2014 at 23:41 | vote | accept | Greg Egan | ||
| Jul 28, 2014 at 17:41 | history | edited | darij grinberg | CC BY-SA 3.0 |
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| Jul 28, 2014 at 17:23 | history | edited | darij grinberg | CC BY-SA 3.0 |
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| Jul 28, 2014 at 15:24 | comment | added | darij grinberg | You're welcome! Let me know if something is wrong. | |
| Jul 28, 2014 at 15:24 | history | edited | darij grinberg | CC BY-SA 3.0 |
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| Jul 28, 2014 at 15:16 | comment | added | Greg Egan | Thanks! It might take me some time to work through this and be sure I understand it. | |
| Jul 28, 2014 at 14:41 | history | answered | darij grinberg | CC BY-SA 3.0 |