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Mar 10, 2010 at 13:57 comment added Amitsur lol, of course! Thanks Georges Elencwajg. I guess I need to get some rest. Thank you all for your useful comments.
Mar 10, 2010 at 13:46 comment added Georges Elencwajg Dear Amitsur, perhaps it seems less strange if you realize that you can take f=x+x^{-1} and that x then satisfies the equation x^2-fx+1=o, so that 1 and x generate A as a k[f]-module .
Mar 10, 2010 at 13:27 history edited Harry Gindi CC BY-SA 2.5
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Mar 10, 2010 at 13:23 history made wiki Post Made Community Wiki by Harry Gindi
Mar 10, 2010 at 13:06 comment added Pete L. Clark See the comments above. This is incorrect (note: being finitely generated over k is clearly necessary.)
Mar 10, 2010 at 13:02 comment added Amitsur Thank you guys. I'll check the sources you gave me. So, the Laurent polynomial ring A=k[x,x^{-1}] must be finitely generated k[f]-module for some f in A then. This is kind of strange, isn't it?
Mar 10, 2010 at 12:47 history edited Harry Gindi CC BY-SA 2.5
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Mar 10, 2010 at 12:42 history answered Harry Gindi CC BY-SA 2.5