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Jul 22, 2014 at 21:40 history edited David E Speyer CC BY-SA 3.0
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Jul 22, 2014 at 20:00 comment added David E Speyer I have now edited in Don's point.
Jul 22, 2014 at 20:00 history edited David E Speyer CC BY-SA 3.0
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Jul 22, 2014 at 19:54 comment added David E Speyer @so-calledfriendDon Excellent point! You are right! Strange that Bhargava doesn't point that out; this argument shows that Bhargava's formula is always an upper bound.
Jul 22, 2014 at 19:44 comment added so-called friend Don Doesn't the hypothesis in Theorem 1.3 only require what you said for all large enough p? So why can't you (or can you?) run your argument up to an arbitrarily large finite height to get an arbitrarily small upper density, and hence a density of 0?
Jul 22, 2014 at 15:17 history answered David E Speyer CC BY-SA 3.0