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Feb 20, 2015 at 15:50 comment added lost1 No, I was looking for a martingale, not a local martingale.I am saying the conditions given are sufficient conditions for martingales. I want to see why they are not necessary conditions.
Jul 22, 2014 at 7:28 comment added Olivier Leveque You could let $B$ start somewhere else than $0$, but then I agree there is always a possibility that $B$ comes back at $0$ at some point. There are similar examples in higher dimensions, where $B$ is transient, but OK, this does not guarantee that $M$ is strictly speaking continuous. Regarding your second comment, we are looking for a local martingale, not a martingale.
Jul 22, 2014 at 2:35 comment added Nate Eldredge I'm confused: does $B_t$ start at 0? Then surely $M_t$ is not continuous? And aren't we looking for a martingale, not a local martingale?
Jul 21, 2014 at 16:14 history answered Olivier Leveque CC BY-SA 3.0